Clouds
Nacreous clouds
- A form of PSC (~10 microns)
- Formed by waves over mountains
- Text and other locations: nacreous clouds
- PSC
- Polar stratospheric clouds
- Polar stratospheric clouds
- Located about 15-25km
- Winter polar stratosphere is very cold 180-190 K
- HNO3 and water form ice clouds
- Ice surfaces catalyse conversion of HCL to CL which attacks ozone and creates ozone hole
- Contains:
- H2O, h2SO4, HNO3, HCL
- H2O, h2SO4, HNO3, HCL
Noctilucent Clouds
- Only appear in polar regions
- Size ~.1 microns or smaller
- Very thin layer clouds:
- Hard to see over head
- Only visible at twilight or later w/ a long path for illumination
- Hard to see over head
- At the summer mesopause
- Very cold ~100-140 K
- 173 to 133 degrees celcius
- 173 to 133 degrees celcius
- Frozen water
- Ccn probably meteoritic dust
- Wave structures revealed in ice formation
- Can be warning of increased methane (CH4)`
Lapse Rates
- Environmental
- Γe environmental lapse rate
- dT/dz = ΔT /ΔZ = - Γe
- 'dry' adiabatic
- g/Cp = Γdry
- g/Cp = Γdry
- 'moist' adiabatic
- g/Cp = Γmoise
- g/Cp = Γmoise
- ΓMoist < ΓDry
- dT/dz = ΔT /ΔZ = - Γe
- Depends on the planet and the major gas
- AIR PARCEL(AP)
- Think of an isolated unit of air maintaining its integrity
- This doesn't work for long because of exchange of molecules etc
- Think of an isolated unit of air maintaining its integrity
- Lapse rate is how the temp is going to change in height
- A steep lapse rate means large temperature change
- Adiabatic
- No exchange of energy with outside
- No exchange of energy with outside
- Cooling
- Important in Cloud formation and rain
- Important in Cloud formation and rain
- Mean global rate
- ~6.5 C/Km
- Inversion, temperature increases with height
- ~6.5 C/Km
- Specific heat @ constant pressure Cp energy add to raise temp 1Celsius for 1kg @ constant pressure
- Specific heat @ constant Volume Cv energy add to raise temp 1Celsius for 1kg @ constant pressure
- Cp(air) = 1007 J/kg/Kelvin
- For one Kg you have to have supply 1007 joules for 1 degree celcius difference
- For one Kg you have to have supply 1007 joules for 1 degree celcius difference
- Cv(air) = 700 J/kg/Kelvin
- − T2 ) / (Z2 – Z1) = (-g)/Cp
- Dry adiabatically
- Dry adiabatically
- -(T1MCp)
- Extract heat
- Extract heat
- + Mg(z2-z1)
- Add potential energy
- Add potential energy
- + CpMT2
- Add heat
- Add heat
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