CSE 2031 Lecture 5

void makeDouble(int* x)

{

    *x = 2* *x;

}

 

* modifies a pointer

This in English is makeDouble takes an integers pointer

Then the integers pointer is modified.

An '&' sign is a pointer. int I, *p; /* means that there is an integer I and an integer memory reference *p;

An expression has a type and value.

*(r=&j) *= *p

**p dereferences p

 

Pointer to void

• Why do pointers have types?
  
  • So we can dereference them
    
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